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In how many ways can a teacher arrange 10 students in the front row if there are 60 total students?
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@ganeshie8
\[60P10=\frac{60!}{50!}\]
10! 60! / (10! 50!) = 60! / 50!
=273,589,847,231,500,800
?
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The question asks for arrangements. Therefore permutations are required.
Is that the answer? or no
My calculator took it to 10 significant figures. Therefore I can't be sure of your last 8 digits.
@AravindG
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