Question

(y^2-81/6y+12)*(y+2/y-9)

Answer 1

Hints:

y^2 - 81 factors to (y-9)(y+9)

6y+12 factors to 6(y+2)

Answer 2

do you understand what he means?

Answer 3

I think so. It would become (y-9)/6, right?

Answer 4

Close, but not quite right....

Answer 5

try again kiddo :P

Answer 6

\[\frac{(y^2-81)}{(6y+12)}*\frac{(y+2)}{(y-9)} = \frac{(y-9)(y+9)}{6(y+2)}*\frac{(y+2)}{(y-9)} =\]