Question

Determine if x = 2 is a root for the function: f(x) = 2x3 - 22x2 + 76x - 80

Answer 1

if 2 is a root f(2) = 0 check if true

Answer 2

how do i check tho

Answer 3

check f(2)

Answer 4

f(x) = 2x3 - 22x2 + 76x - 80
f(2) = put 2 where x is and simplify

Answer 5

f(x) = 2(x)3 - 22(x)2 + 76(x) - 80
f(2) = 2(2)3-22(2)2+76(2)-80

Answer 6

make sense?

Answer 7

yeah thanks