Question

Use substitution method. Answer as an ordered pair.
2x-y=10
3x-2y=8

Answer 1

\[2x-y=10...(1)\]
\[3x-2y=8...(2)\]
Isolate y by adding y and subtracting 10 to both sides
\[2x-y\color{red}{+y-10}=10\color{red}{-10+y}\]
we get
\[2x-10=y...(3)\]
now substitute (3) into (2)
\[3x-2y=8\]
\[3x-2(2x-10)=8\]
solve for x