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what is the solution for –2(x – 3) ≥ 5 – (x + 3) ?
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\(–2(x – 3) \ge 5 – (x + 3)\) \(-2x+6\ge5-x-3\) \(-2x+6\ge2-x\) Solve for x. Does that help? @jaderbrown
yes, thank you. how should I graph the equation ?
what do u get when u solve for x?
-4 is less than or equal to -x
so its a closed circle and you shade it to the left or right?
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\(-2x+6\ge2-x\) \(6\ge2-x+2x\) \(6-2\ge x\) \(4\ge x\) \(x\le4\) this means that x can take any values less than 4 and also 4. what are the values less than 4?
3,2,1 and lower
in a number line these values in the right or left?
the left, I got it now. thank you so much!
Welcome:)
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