Question

4i(2+3i)

Answer 1

Start by distributing the 4i

Answer 2

please teach me how

Answer 3

=4i(2)+4i(3i)
=8i+12i^2
=8i+12(-1)
=-12+8i

Answer 4

is that it

Answer 5

So we have 4i(2 + 3i)

if we distribute the 4i we have to multiply 4i by 2 and by 3i so we end up with:

8i + 12i^2

BUT i^2 = - 1, so we have:

8i + 12(-1)

= 8i - 12

yes you did it! good job.