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Find the surface area of a square pyramid with a slant height of 23 and a base side measure of 10.
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Help please? My semester ends tomorrow!
I believe the fomula is S=B1/2Pl
Where B is the area of the base P is the perimeter of the base and l is the slant height
is pretty much what you have take a look at one face, the bottom/base is 10, going upwards, is really just a triangle
get the area of THAT triangle, now you have 4 sides, thus 4 triangles, add all those up then add the bottom/base, which is just a 10x10 rectangle
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