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For the function f(x)=1/x, what is the equation of the tangent line at x=1.
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f ' (x) = -1/x^2 f ' (1) = -1 = Slope f (1) = 1 giving us coordinate (1,1) So our slope is Y-1=-1(X-1)
simplified makes it y=-x+2?
Yep!
thanks!
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