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OpenStudy (anonymous):
write the series in summation notation and find the sum, assuming the suggested pattern continues. 6+2+2/3+2/6+2/9+...+2/729
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OpenStudy (anonymous):
6/(3n)
OpenStudy (anonymous):
is that the sum?
OpenStudy (anonymous):
\[6\sum_{n=1}^{\infty}\frac{1}{3n}\]
OpenStudy (anonymous):
Well, I'm sorry, if the series stops at 2/729 then the upper limit isn't infinity...
OpenStudy (anonymous):
the assumption is it continues.
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