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factor completely: 2x ^5+x ^4-10x^3-16x ^2-8x+80
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I got \[x ^{3}(2x+5)(x-2)-8(2x+5)(x-2)\]
wrong
hint: the last number is the multiple of what?
What do you mean?
I split the original in half and then factored from there and brought them back together at the end and that's what you get
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Did you get an answer?
there is really 3 factor
Can you explain?
|dw:1369969411317:dw|
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