Question

Is anyone here good at advanced calculus?

Answer 1

Like analysis?

Answer 2

I got an A, I would still not say Im good:)

Answer 3

HI IAM GOOD AT ADVANCED CALCULUS WHAT U WANT

Answer 4

im just kidding xD i am just starting to learn basics of calculus

Answer 5

http://gyazo.com/c2a712e495a1823641bcddb0891000b5

Answer 6

do you have def of cut?

Answer 7

@FutureMathProfessor do you have a definition of cut? we might call it something different?

Answer 8

is this sequent calculus?

Answer 9

It's advanced calculus. It's all theory

Answer 10

Yes I know...what is the definition of a cut? you should have that...

Answer 11

I am done with analysis and complex analysis i.e, all the advanced calculus one needs to graduate:)

Answer 12

Even if I google cut I don't get anything that seems to be fitting....Hence a definition would be nice......

Answer 13

Take any two non empty disjoint sets A and B of Q, such that A union B is Q. This collection (A,B) is called Dedekind cut?

Answer 14

@FutureMathProfessor if you would like help you need to answer questions...

Answer 15

zzrock3r what does it feel like to complete all this math?? do u see the world different

Answer 16

no I don't see the world...I see my school:)

Answer 17

:(

Answer 18

the whole world looks like 0's and 1's

Answer 19

its like the matrix

Answer 20

jk:P

Answer 21

lol

Answer 22

can you solve like pretty much anything?? like can you look at a flower and see the pattern its growing in and write an equation for its growth and how its leaves will spread?

Answer 23

If I think a cut is when two disjoint sets form the set that they are a sub set of.

Answer 24

lol

Answer 25

YOU CAN CANT YOU!! that wud be the life!

Answer 26

i wonder if i learn enuff math, ill be able to just do infinite series sums and all kinds of math all in my head!! then when i walk down the street i can see an equation for everything i see!

Answer 27

Medals 0 let C_r be defined as you said
if c is in C_r then c is no in Q-C_r
because c is in Q and thus cant be greater than r in Q and less then r in Q at the same time, by transitivity... thus the set C_r and Q-C_r are disjoint.
let q be in Q
then q < r or q >= r thus q is in C_r union Q-C_r (this is trivial)