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OpenStudy (anonymous):
Factor completely: 28a3b4 + 20a2b2 − 16ab3 4ab(7a2b + 5a − 4b2) 4ab2(7a2b + 5a − 4b) 4ab2(7a2b2 + 5a − 4b) 4ab(7a2b3 + 5a − 4b)
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OpenStudy (blurbendy):
The second one works
OpenStudy (blurbendy):
no
OpenStudy (blurbendy):
it's the third one.
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