Question

An isosceles triangle has an area of 156ft^2. If the base is 16, what are the lengths of the legs?

Answer 1

Area = ½ × b × h
b = base
h = vertical height

Answer 2

Area = ½ × b × h

156 = 1/2 * 16 * h

156 = 8 * h
---- -----
8 8

19.5 = h

Answer 3

so then both legs equal 19.5 right?or is that the height...