Question

Two buses leave towns 616mi apart at the same time and travel toward each other. One bus travels 8mi/h slower than the other. If they meet in 4 hours, what is the rate of each bus?

Answer 1

let the speed of the busses be x and x+8 mi/h
the n since they move in opposite direction relative speed =x+x+8=2x+8
now by the problem
(2x+8)*4=616
or 2(x+4)*4=616
or (x+4)=616/8
x+4=77
x=73
thus their speed are 73 and 81