Question

solve for a . a= square root of (19-3a) +5

Answer 1

a = √(19-3a + 5
√(19-3a) = a-5

Square both sides

(19 -3a) = (a - 5)²
19 - 3a = a² - 10a +25

Combine all like terms

a² - 10a +3a +25 -19 = 0
a² -7a +6 = 0

(a-6) (a-1) = 0

a = 6,1

Now put these values in your original equation and check for extraneous solutions.