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find the inverse of the given function f(x)=3/24x-13
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\[f(x)=\frac{3}{24x-13}\]?
no its f(x)=\[\frac{ 3 }{ 24 }x-13\]
isn't that the same as \[f(x)=\frac{1}{8}x-13\]?
in any case, if you wanted to solve \[\frac{1}{8}x-13=5\] you would a) add 13 to get \(\frac{1}{8}x=5+13\) and then multiply by 8 to get \(x=8(5+13)\)
that is what the inverse does, add 13, multiply by 8 i.e. \[f^{-1}(x)=8(x+13)\]
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okay thank you
yw
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