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How do you factor a binomial with a odd exponent. This format (X^3)-8
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can you write 8 as a cube ?
it's a find the limit problem thee numerator is (x-2) the denominator is the format
if you get (x^3)-8 into the form of a difference of cubes you will be able to factorise , one of the factors wil be (x-2)
can you play this otu for me?
Sum of cubes\[a^3 + b^3 = (a + b)(a^2 – ab + b^2) \]Difference of cubes\[a^3 – b^3 = (a – b)(a^2 + ab + b^2)\]
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ah okay thx i am going to try that
hows it going?
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