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OpenStudy (anonymous):
a 2.0 kg block on an incline at a 60.0 degree angle is held in equilibrium by a horizontal force, what is the magnitude of this horizontal force (disregard friction)
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OpenStudy (jfraser):
find the components of the weight vector and treat each case (horizontal and vertical) independently. Because the block is not accelerating, the \(\Sigma F_x =0\) and \(\Sigma F_y = 0\)
OpenStudy (anonymous):
16.97
OpenStudy (jfraser):
a number without units or work is worthless
OpenStudy (anonymous):
Newtons
OpenStudy (anonymous):
2*9.8sin60==16.97N
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