What are the points of discontinuity? Are they all removable?

y = (x-3)/x^2 - 12x + 27

Question

What are the points of discontinuity? Are they all removable?

y = (x-3)/x^2 - 12x + 27

myininaya · Answer

When is the bottom 0?

myininaya · Answer

For what values of x make the bottom 0?

anonymous · Answer

not sure?

myininaya · Answer

So you should be able to solve an equation in this form ax^2+bx+c=0 by now.
I'm guessing this since this is a type of problem that occurs after learning that.

myininaya · Answer

Do you know how to factor?

myininaya · Answer

Or even use the quadratic formula to solve a quadratic equation?

myininaya · Answer

You can even do completing the square.

anonymous · Answer

so x^2+12x+27=0?

anonymous · Answer

how do i do that?

myininaya · Answer

Do you have -12x or +12x?

anonymous · Answer

its postive 12x

myininaya · Answer

Hmmm...So the problem above is written/typed wrongly I assume.
Okay You should know how to factor the polynomial x^2+12x+27

myininaya · Answer

Find two factors of c that add up to be b (you can do this when the coefficient of x^2 is 1 which in this problem it is)

myininaya · Answer

In other words find two factors of 27 that add up to be 12.

anonymous · Answer

its like this |dw:1370027288868:dw|