Question

limit x->1
arcsec(2-x)/x^2

Answer 1

can i write it as?
\[\Huge \frac{1}{\cos^{-1}(2-x) \times x^2}\]

Answer 2

actually im solving a limit,so ill use LH,now it will be 0 on seperate derivating right?

Answer 3

@yrelhan4

Answer 4

@phi

Answer 5

@RadEn

Answer 6

@.Sam.

Answer 7

no, 1/acos(A) ≠ asec(A)

in this problem you need to find A such that sec(A)=1 or 1/cos(A) = 1
then do the limit A/x^2

Answer 8

why is it so? and this gives 0 too,and answer is 0 too.
Maybe a co-incidence

Answer 9

isn't 1/acos(1) = 1/0 = not defined ?

Answer 10

hmm..yeah