A certain mountain has an elevation of 19895 ft in 1913, the glacier on this peak covered 6 acres.?
By 2005 this glacier had melted to only 1 acre. The yearly rate of change is __acres/year.
what is the equation that gives the acreage of the glacier. t years after 1913
A=

Question

A certain mountain has an elevation of 19895 ft in 1913, the glacier on this peak covered 6 acres.?
By 2005 this glacier had melted to only 1 acre. The yearly rate of change is __acres/year. 
what is the equation that gives the acreage of the glacier. t years after 1913
A=

anonymous · Answer

@physicsboffin @jhonyy9 @GoldPhenoix

johnweldon1993 · Answer

well .....not sure about the elevation part of it *not needed here*

but in 1913 the glacier covered 6 acres

in 2005, it was down to 1 acre

so that is a 92 year difference....with 5 acres lost.

so they lose on average

5 / 92 = .05 acres a year

*makes sense because in the 92 years....Times .05 is indeed 5 acres

can you solve the second part now??

anonymous · Answer

@johnweldon1993 im totally lost with this particular problem