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Someone wanna help me out? 2^(4x+2)=8^(x-3)
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Hint: logarithms
log two of both sides gives 4x+2 = (x-3)log_2(8) so 4x+2 = 3(x-3)
do you see why?
when I write log I mean log base 2 log(2^(4x+2)) = (4x+2)log(2) = 4x+2
-_- Im retarded. Yeah, I got -11
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and on the rhs log(8^(x-3)) = (x-3)log(8) now 2^? = 8 3 so 3(x-3)
correct
Thanks!
np
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