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Mathematics 21 Online
OpenStudy (anonymous):

Determine the point at which the graph of the function below has a horizontal tangent line y = 6x2 + 7

OpenStudy (anonymous):

\[y=6x^2+7\] The tangent line will be horizontal when its slope is zero. Its slope is equal to \(y'\), so you have to solve \(y'=0\) for \(x\).

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