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OpenStudy (anonymous):
Simplify the trigonometric expression? sin^2 θ/ (1 - cos θ)
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OpenStudy (raden):
sin^2 θ = 1 - cos^2 θ
OpenStudy (raden):
the use the difference square formula : a^2 - b^2 = (a+b)(a-b) so, sin^2 θ/ (1 - cos θ) = (1 - cos^2 θ)/ (1 - cos θ) = (1 + cos θ) (1 - cos θ)/ (1 - cos θ) cancel out the same term, and get ur answer
OpenStudy (raden):
* then
OpenStudy (anonymous):
thank you very much! :)
OpenStudy (raden):
wlcm
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