Claire has received scores of 85, 88, 87, and 85 on her algebra tests. What is the minimum score she must receive on the fifth test to have an overall test score average of at least 88?

Question

anonymous · Answer

average of the 5 tests must be at least 88

average- sum of all the test scores divided by the total number of test

assume that the 5th test score is "x"

then we can write the inequality as 
$$\frac{85+88+87+85+x}{5} \ge 88$$

solve for x

anonymous · Answer

depend's, was she a skeeze?

anonymous · Answer

so how do you solve for x mane

anonymous · Answer

start by multiplying 5 to both sides

anonymous · Answer

which side do I start on

anonymous · Answer

...
BOTH SIDES

anonymous · Answer

imagine as if it were a regular equation and just solve it...

anonymous · Answer

got you then what do I do after that

anonymous · Answer

english please

you solve for x be subtracting the individual test scores from both sides

anonymous · Answer

thanks mane