Question

between what two intergers does log 2 58 lie

Answer 1

if:\[\log_2{58}=x\]then this implies that:\[58=2^x\]so find the largest integer \(x_1\) such that \(2^{x_1}\lt58\) - that will give you the lower integer.
then find the smallest integer \(x_2\) such that \(2^{x_2}\gt58\) - that will give you the upper integer.