Question

Solve the system of linear equations by the substitution method

x = 3y + 30
3x + 6y = 0
Can someone show me the steps as to how to do this? Thanks!

Answer 1

x = 3y + 30
3x + 6y = 0

now we sub x into the 2nd equation since x = 3y + 30

3(3y + 30) = 0

Answer 2

3(3y +30 ) +6y = 0
sorry

Answer 3

9y + 90 + 6y = 0
15y + 90 = 0
15y = -90
y =-6
now can you find x value?

Answer 4

Good job demonstrating and not just handing out the answer, @AonZ.