Question

http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_s08_qp_1.pdf Q26

Answer 1

........you will be suspended if you don't take this off............not by me though

Answer 2

@primeralph it's from 2008

Answer 3

@ameeron I'm sorry about that. You can post it.

Answer 4

\[I\propto \frac1{x^2}\\\quad \Downarrow\\I(x)=\frac{\alpha}{x^2}\]

Answer 5

\[I(r)=\frac\alpha{r^2}=8.0[\text{ μm}] \]
\[\alpha=r^28.0[\text{ μm}]\]

\[I(2r)=\frac\alpha{(2r)^2}=\frac{r^28.0[\text{ μm}]}{4r^2}\]