find value of x and y (1+i) y ka squre + (6+i) = (2+i)x
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sam (.sam.):
\[ (1+i) y ka^2 + (6+i) = (2+i)x \]?
OpenStudy (anonymous):
heh listen if u r not able to understnd can i attached the file and tell u whch qustion is neded to be done
sam (.sam.):
Yeah attach it
OpenStudy (anonymous):
OpenStudy (anonymous):
r u able to see the qustionss
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OpenStudy (anonymous):
i want answers of question no. 2 b and c part and q3 and q1. f part pllzzz help mee
OpenStudy (gorv):
((1+i)y)^2+(6+i)=(2+i)x
(1+i)^2*y^2+6+i=2x+ix
(1-1+2*i*1)*y^2+6+i=2x+ix
i2y^2+6+i=2x+ix
6+i(2y^2+1)=2x+ix
now compare real and imaginary part of both side
2x=6 and x=2y^2+1
x=3 3=2y^2+1
2=2y^2
y^2=1
y= +-1
ans (x,y)=(3,1) or (3,-1)
OpenStudy (anonymous):
which answer is this
OpenStudy (anonymous):
^ yeh symbol kiska hai
OpenStudy (gorv):
y^2 means y square
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OpenStudy (gorv):
this is the answer of your question
OpenStudy (anonymous):
kk thanks can u solve more qustions that i have post
OpenStudy (gorv):
yeah tell
me
OpenStudy (anonymous):
OpenStudy (anonymous):
i have attached the qustions in this i need answer of q1.f) part and q2 c part and q3. answer plzzzzzz provide me
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