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the numerical value of sin 6°.sin 42°.sin 66°.sin 78°
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is it sqrt(3)/8
no
answer is 1/16
its already solved in ur book but it is done as with tans
of course
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yup just iguessed it don't worry
just group as 1/4 (2sin6sin66)*(2sin42sin78)
now use 2sinAsinB=cos(A-B)- cos(A+B)
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