Question

Help plz!!! Open to see the question

Answer 1

i need help in Question no. 10 here ^

Answer 2

Methyl Alcohol one

Answer 3

omg we just done them last wk

Answer 4

really ??? ^_^

Answer 5

yes and i had exam on it also

Answer 6

i am good at it but cant solve this Q10

Answer 7

@RANE u said u know this ???

Answer 8

Which grade are you guys in?

Answer 9

11th grade

Answer 10

Okay, so you've done thermodynamics?

Answer 11

yup

Answer 12

this question is solved by adding and subtracting equations from the data

Answer 13

and multiplying them to get the equation given in Number 1

Answer 14

Thats exactly what I'm trying to do.

Answer 15

although i am good at it ..but this is a bit confusing one

Answer 16

so are u solving it ? @aditkarekatte

Answer 17

Is it -189.4?

Answer 18

i have not solved it

Answer 19

can u give me some starting tips ?

Answer 20

I see. Try reversing equation 3, and divide equation 2 by 2. Then add like a boss. B-)

I think.

Answer 21

And divide equation3 by 2 as well. I think I forgot to do that.

Answer 22

wait i am doing

Answer 23

(Y)

Answer 24

i have divided eqn 3 by 2

Answer 25

what to do with eqn 2 ?

Answer 26

multiply by 2 ?

Answer 27

divide that by 2 as well. Subtracting 2O2 - 3/2O2 gives you the 1/2O2 you need.

Answer 28

ok

Answer 29

MIla kya?

Answer 30

wait yar i am doing ...

Answer 31

how did u get 2O2 in eqn 2 ?

Answer 32

No, its 2O2 when you add eqn 1 + eqn 2

Answer 33

okay...first i have to add 1 & 2 right ? without doing anything else

Answer 34

Yeah. Then reverse 3 and divide by 2.

Answer 35

Then add, and Bob's your uncle.

Answer 36

when u add eqn 1 and 2 u get 3/2O2

Answer 37

yoy have X2 in eq 2 that makes 1/2O2 to 2*1/2O2 there for O2.
plus O2 from eq 1 you have 2 O2

Answer 38

when you moltiplay or divide you do so to ALL ...an the ΔΗ

Answer 39

thanks to all!!!!! thank u very much

Answer 40

give me the resalty to verify....

Answer 41

i am going for my dinner..... so u do anything else ...i am coming in 10 mins okay?.....then i'll tell u

Answer 42

i am not sure if i will be on line then
I FIND 792.2

Answer 43

-792.2

Answer 44

Multiply eqn 2 by 2 then add with eqn 1

Answer 45

Did you get it?

Answer 46

2H2 + C + 202 --> 2H2O +CO2 (H=-966)

Answer 47

is this correct till here ^

Answer 48

yap

Answer 49

okay now this is next

Answer 50

Go on...

Answer 51

divide eqn 3 by 2
CH3OH +3/2 O2 -----> CO2 + H2O (H=-173.8)

Answer 52

Yes.

Answer 53

ok

Answer 54

Subtract Both eqns above ^^

Answer 55

No no no. Add 1 and 2, then sebtract 3

Answer 56

i added both already eqn 1 + 2*eqn 2

Answer 57

CH3OH +3/2 O2 -----> CO2 + H2O (H=-173.8)
reverce that

Answer 58

then add

Answer 59

add with ??

Answer 60

2H2 + C + 202 --> 2H2O +CO2 (H=-966)

Answer 61

it has 2H2O o_o ...how will this cancel ?

Answer 62

note: when you reverse ghange the sinht to ΔΗ

Answer 63

have nt you divide by 2????

Answer 64

i divided only eqn 3 by 2....not any other eqn

Answer 65

if we divide this by 2 it will ruin others

Answer 66

give me a moment to look it up from the begining

Answer 67

That's correct, yes.

Answer 68

okay

Answer 69

equation 3 is given wrong!!!!

Answer 70

what ??

Answer 71

Yes, I found that the water does not get balanced. But I overlooked it; it must be a mistake. You can always work around that. :)

Answer 72

so how did u got that -792.2

Answer 73

*overlooked as in intentionally

Answer 74

2 CH3OH + 3O2 ->2 CO2 + 4 H2O

Answer 75

that is the correct eq 3

Answer 76

so how will i get this methyl alcohol eqn ?

Answer 77

use my eq3
do as we have sad so far.....

Answer 78

eq1 as it is
eq2 x2
my eq3 div by 2 and revers
add

Answer 79

this paper you have has also wrong numbers in Q1

Answer 80

yes

Answer 81

my answer is -822.2

Answer 82

-394
-286x2= -572
-347.6/2=-173.8
reverse = +173.8
total=-792.2

Answer 83

i got it

Answer 84

thanks

Answer 85

ok