Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

How to factor x³-6x²+12x-8

OpenStudy (asnaseer):

do you know how to factor \(a^3-b^3\) that will help you if you know this factorisation

OpenStudy (anonymous):

calculator

OpenStudy (asnaseer):

note that \(8=2^3\)

OpenStudy (anonymous):

yeah i know how to do a3−b3 but how does that help

OpenStudy (anonymous):

?

OpenStudy (asnaseer):

try using it to first factorise \(x^3-8\)

OpenStudy (asnaseer):

you should then spot what the next step should be

OpenStudy (anonymous):

sorry, i dont see it. I get (x-2)(x^2+2x+4)

OpenStudy (mertsj):

Do you know synthetic division?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

i just end up with (x-2)(x^2+2x+4)-6x(x+2)

OpenStudy (mertsj):

Have you had the rational roots theorem?

OpenStudy (mertsj):

Shouldn't that be -6x(x-2)

OpenStudy (anonymous):

no

OpenStudy (anonymous):

x³-6x²+12x-8 was rearranged into x³-8-6x²+12x

OpenStudy (anonymous):

see?

OpenStudy (mertsj):

\[-6x^2+12x=-6x(x-2)\]

OpenStudy (mertsj):

See?

OpenStudy (anonymous):

yeah

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!