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How to factor x³-6x²+12x-8
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do you know how to factor \(a^3-b^3\) that will help you if you know this factorisation
calculator
note that \(8=2^3\)
yeah i know how to do a3−b3 but how does that help
?
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try using it to first factorise \(x^3-8\)
you should then spot what the next step should be
sorry, i dont see it. I get (x-2)(x^2+2x+4)
Do you know synthetic division?
no
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i just end up with (x-2)(x^2+2x+4)-6x(x+2)
Have you had the rational roots theorem?
Shouldn't that be -6x(x-2)
no
x³-6x²+12x-8 was rearranged into x³-8-6x²+12x
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see?
\[-6x^2+12x=-6x(x-2)\]
See?
yeah
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