Question

sim[plify the squeare root of 24

Answer 1

do you know that
- (for \(a>0\)), \(\sqrt{a^2}=a\)
- (for \(a>0\)), \(\sqrt{ab}=\sqrt{a}\sqrt b\) ?
If so, write the number 24 as a product of two numbers, one of which is a perfect square.
and then you're almost done, use the properties I wrote above.

Answer 2

what's your answer?