Question

F=(x) 4x^3 - 12x^2 -16x WHat are the zeros of the function? What are their multiplicties?.

Answer 1

The answer is the numbers -1, 4, and 0 are zeros of the multiplicity.

Answer 2

Hoow?

Answer 3

\[ 4x^3 - 12x^2 -16x\]
\[=4x(x^2-3x-4)\] is a start

Answer 4

then factor as
\[4x(x-4)(x+1)\]

Answer 5

Oh factoring lmao =.=

Answer 6

sorry for the bother

Answer 7

\(4x=0\iff x=0. x-4=0\iff x=4,x+1=0\iff x=-1\)