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Find the product. (a^3 + 8)(a^3 - 8)
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Remember, (b+c)(b-c) = b² - c²
Or you can use FOIL or box method.
Okay! is it a^6 - 512?
a^6 - 64***** i mean
8² = 512??? Try again.
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Yep, \(\boxed{a^6 - 64}\)
\[\large (a^3+8)(a^3-8)\]\[\large a^3(a^3-8)+8(a^3-8)\]\[\large (a^3)(a^3)-(a^3)(8)+(8)(a^3)-(8)(8)\] now just expand this and you'll have your answer
\[\large a^{(3+3)}-8a^3+8a^3-64\]hope that helps too... :\
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