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Mathematics 16 Online
OpenStudy (anonymous):

Find the product. (a^3 + 8)(a^3 - 8)

geerky42 (geerky42):

Remember, (b+c)(b-c) = b² - c²

geerky42 (geerky42):

Or you can use FOIL or box method.

OpenStudy (anonymous):

Okay! is it a^6 - 512?

OpenStudy (anonymous):

a^6 - 64***** i mean

geerky42 (geerky42):

8² = 512??? Try again.

geerky42 (geerky42):

Yep, \(\boxed{a^6 - 64}\)

OpenStudy (jhannybean):

\[\large (a^3+8)(a^3-8)\]\[\large a^3(a^3-8)+8(a^3-8)\]\[\large (a^3)(a^3)-(a^3)(8)+(8)(a^3)-(8)(8)\] now just expand this and you'll have your answer

OpenStudy (jhannybean):

\[\large a^{(3+3)}-8a^3+8a^3-64\]hope that helps too... :\

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