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Precalculus
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2 times the cubed root of 7b-1 equals 4
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\[2\times \sqrt[3]{(7b-1)} = 4\]
this??
@randomguy111
yep!
k, assuming it it... just remember to always balance the 2 sides of your equation so LHS /2 = RHS /2 2 x cubed root of (7b-1) = 4 2 x cubed root of (7b-1) /2 = 4 /2 cubed root of (7b-1) = 2 now cube both sides (^3), so cubed root of (7b-1) = 2 cubed root of (7b-1) ^3 = 2 ^3 (7b-1) = 8 can u take it from here?
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So b would equal 9/7 ?
that what i got, yep
Awesome! Thank you so much! Hey I might need more of your help lol
sure, just gonna finish helping constance first
Okay just let me know :)
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