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Mathematics 15 Online
OpenStudy (anonymous):

2x√7(3x√7)

OpenStudy (anonymous):

@saifoo.khan

OpenStudy (anonymous):

\[2x(3x)\sqrt{7}\sqrt{7}\]

OpenStudy (anonymous):

\[6x \sqrt{49}\]

OpenStudy (saifoo.khan):

6x^2 rest is right.

OpenStudy (anonymous):

\[6x ^{2}\sqrt{49}\]

OpenStudy (saifoo.khan):

simplify the root.

OpenStudy (anonymous):

it would be 7

OpenStudy (saifoo.khan):

Indeed.

OpenStudy (anonymous):

lol :)

OpenStudy (anonymous):

so I can't multiply them right it's not like terms \[6x ^{2} \] and 7

OpenStudy (saifoo.khan):

But you can multiply 6and 7. Making it something.

OpenStudy (saifoo.khan):

I gtg guys. See ya awl later.

OpenStudy (anonymous):

\[42x ^{2}\]

OpenStudy (anonymous):

Thanks @saifoo.khan

OpenStudy (saifoo.khan):

OpenStudy (anonymous):

nice :)

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