Please solve 1.)4 − 3x = 7x − 6 2.)8 + 4x = −10 + x
Move the constants to one side and the varibles to another, then divide by the number in front of the varible. \[ 4-3x=7x-6\] \[ -3x - 7x = -6 - 4\] You should be able to take it from there
-3x-7x=-6-4......transpose 7x to other side and 4 -10x=-10.....add the like terms x=1.....divide both side by -10 and get your answer
4 − 3x = 7x − 6 Put x on right and the rest on the other part(i mean afte= ) 4+6=7x+3x 10=10x x=10/10 x=1
after*
8 + 4x = −10 + x same will be here 4x-x=-10-8 3x=-18 x=-18/3 x=-6
Thank you!! I wrote that all down so I could actually understand the problem
Hahaha okay if you don't understand I'll explain you once again :)
We just have to find x :)
8+4x=-10+x 4x-x=-10-8 3x=-18.....divide both sides by 3 x=-6..
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