Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).

y = one thirdx − 3

y = one thirdx + 17

y = −3x − 3

y = −3x + 17

Question

Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).

y = one thirdx − 3

y = one thirdx + 17

y = −3x − 3

y = −3x + 17

anonymous · Answer

3x+y=7
y=-3x+7.....since we know that when two slopes are perpendicular their m1xm2=-1... the answer will be 1/3

anonymous · Answer

i got help but they were very unclear would you please explain?

anonymous · Answer

i dont need all the work just the answer. so please dont waste your time typing it i honestly wont read it.

anonymous · Answer

one third x - 3. I dint see that last comment of yours.

anonymous · Answer

thank you so much :)

anonymous · Answer

It's a pleasure.