Question

Calculate the derivative of the function
2[(x+8)(x^2-1)]^-1/2

Answer 1

Bring down the exponent and then use chain rule

Answer 2

is the answer -(3x^2+16x-1)/((x+8)(x^2-1))^3/2

Answer 3

Is the problem:
\[2[x+8(x^2-1)]^{-1/2}\]

Answer 4

yes

Answer 5

If I'm right then it would be \[\frac{ d }{ dx }g(h(x))=g'(h(x))*h'(x)\]