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Mathematics 7 Online
OpenStudy (anonymous):

Help?

OpenStudy (anonymous):

OpenStudy (anonymous):

@satellite73 @ParthKohli @Zarkon

OpenStudy (anonymous):

\(\sqrt{x^2}=x\) is a start

OpenStudy (anonymous):

then since \(72=36\times 2\) you get \(\sqrt{72}=6\sqrt{2}\)

OpenStudy (anonymous):

so "final answer" would be \[6x\sqrt{2}\]

OpenStudy (anonymous):

@satellite73 ?

OpenStudy (anonymous):

@satellite73

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