Question

what are the real or imaginary solutions of the polynomial equation::::: x^3-8=0

Answer 1

When it's cubed there are no imaginary solutions
x^3=8
x=2

Answer 2

This is difference of cubes form.

(a³ - b³) = (a -b) ( a² + ab + b² )

x³ - 8 = x³ - 2³

Now use the above formula to write your factors.

Answer 3

Then find your roots