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1/r^8+r^0.4 find ds/dt
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\(\large \frac{ds}{dt}\)? If you're looking for\(\large \frac{ds}{dt}\) then your answer is 0
s=1/r^8+r^0.4 find ds/dt
Do you know anything about the relationship between r and time? Perhpas r is a rate like a speed where position (s) changes over time (t)?
I just know I need to find the derivative
If r does not change with respect to t then the answer is zero; but I would make sure you know that.
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