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How many committees of six can be formed out of a group of twelve Republicans and ten Democrats if no more than four are Democrats?
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First count the possible D/R splits: 4D, 2R 3D, 3R 2D, 4R 1D, 5R 0D, 6R Then for each of these x D, y R, count how many ways you can pick x out of 10 times the number of ways you can pick y out of 12.
The number of committees is given by: \[12C6+(10\times 12C5)+(10C2\times 12C4)+(10C3\times 12C3)+(10C4\times 12C2)\]
kropot72 is correct. Do you understand combinatorial notation?
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