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Solve for x: (2x - 4)2 = 1 A. 2, 3 B. 3/2, 5/2 C. 3/2, 3/5 D. 3/2, -5/2 Solve the equation by graphing. x2 + 5x + 8 = 0 A. {-5, 8} B. {2, 4} C. {-4, 5} D. no real solution Solve the following quadratic equation by a method of your choice: z2 – z – 12 = 0. A. z = 4 or -3 B. z = -4 or -3 C. z = 4 or 3 D. z = ±4
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for the first one distribute
oh yeah I forgot thanks.
(2x-4)(2x-4)=1 can you solve it?
let each of these factor equals 1 and then solve for x
you could also plug in values to see which ones give you 1=1
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is it a
nope
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