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if a=-2 and b= -2, what is the value of (a^3-1) /(b-1)
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\[\frac{ a^3-1 }{ b-1 }\] Is this your equation?
yes
well plug in 2 and solve ^_^
Unfortunately we cannot give out answers, so where do you run into a problem stephanie?
\[\frac{ (-2)^3-1 }{ -2-1 }\]
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since it's a a negative and cubed.. it'll be a negative
\[\frac{ -8-1 }{ -3 }\]
Like Nurali has shown :l
\[\frac{ 9 }{ 3 }\]
which simplifies to 3.. unless I've completely lost my math skills
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3
were we plug in for (-2) ^3, why is it not -6
cause it's -2*-2*-2
a^2=a*a a^3=a*a*a a^4=a*a*a*a etc..
and a^0=1
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oh, I see. I was doing something wrong, thanks ^^
Np
:P
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