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Check my work please... \[\frac{ -18a ^{-8}b ^{-3} }{ 6a ^{-2}b ^{-7} }\]
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-18 / 6 is -3 \[a ^{\left( -8 - (2) \right)} = a ^{-6}\]
and \[b ^{\left( -3 - (-7) \right)} = b ^{4}\]
So then \[\frac{ -3b ^{4} }{ a ^{6} }\]?
yes
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