Question

y+xcosy=(x^2)y
y'=?

Answer 1

y + xcosy =(x^2)y
y' + cosy -xsiny y' = 2xy + x^2 y'
now, can u get y' ?

Answer 2

I can now, I started off with some really funky arithmetic and threw myself off. Thanks! xD

Answer 3

y'=(2xy-cosy)/(1-xsiny-x^2)

Answer 4

yup, that's right

welcome :)