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The gymnast descends from position B and regains contact with the trampoline when it is in its unstretched position. At this position, her centre of mass is 3.2 m below its position at B. Calculate her kinetic energy at the instant she touches the unstretched trampoline
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According to energy conservation, mgh=1/2m(v^2)... That is kinetic energy is exactly equal to the value when he was at his highest position (3.2 metre above). Plug the values, g=9.8, h=3.2 , m= well this value is required , and calculate.
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