Question

A rectangular garden has a width that is 8 feet less than twice the length. Fine the dimensions if the perimeter is 20 feet.

Answer 1

well if the length is l

width = 2l - 8

so the perimeter is normally

P = 2l + 2w

but for your question you have

20 = 2l + 2(2l - 8)

which means

20 = 2l + 4l - 16

all you need to do is collect like terms and then solve for l

when you have l substitute it into

Width = 2l - 8

to find the dimensions.